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December 4, 2012
RMO 2012 solution to Question No. 6

6. Find all positive integers n such that $latex (3^{2n} + 3 n^2 + 7 )$ is a perfect square. Solution: We use the fact that between square of two consecutive numbers there exist no perfect square. That is between $(k^2 )$ and $((k+1)^2 )$ there is no square. Note that $(3^{2n} = (9^n)^2 )$ […]

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December 3, 2012
RMO 2012 solution to Question No. 5

5. Let ABC be a triangle. Let D, E be points on the segment BC such that BD = DE = EC. Let F be the mid point of AC. Let BF intersect AD in P and AE in Q respectively. Determine the ratio of triangle APQ to that of the quadrilateral PDEQ. Solution: Applying Menelaus' […]

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December 3, 2012
RMO 2012 solution to Question No. 4

4. Let X = {1, 2, 3, ... , 10}. Find the number of pairs {A, B} such that A ⊆ X, B ⊆ X, A ≠ B and A∩B = {5, 7, 8}.   Solution:   First we put 5, 7, 8 in each of A and B.   We are left out with 7 elements of […]

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December 3, 2012
RMO 2012 solution to Question No. 3

3. Let a and b are positive real numbers such that a+b = 1. Prove that \( (a^a b^b + a^b b^a \le 1)\) Solution: We use the weighted A.M.-G.M. inequality which states that: \( \frac {w_1 a_1 + w_2 a_2 }{w_1 + w_2} \ge ({a_1}^{w_1} {a_2}^{w_2})^{\frac{1}{w_1 + w_2}} \) First we put \( w_1 […]

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December 3, 2012
RMO 2012 Solution to Question No. 2

2. Let a, b, c be positive integers such that a divides $ (b^5)$ , b divides $(c^5)$ and c divides $ (a^5)$. Prove that abc divides $((a+b+c)^{31})$. Solution: A general term of the expansion of $((a+b+c)^{31})$ is $(\frac {31!}{p!q!r!} a^p b^q c^r)$ where p+q+r = 31 (by multinomial theorem; this may reasoned as following: […]

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December 3, 2012
RMO 2012 solution to Question No. 1

1. Let ABCD be a unit square. Draw a quadrant of a circle with A as the center and B, D as the end points of the arc. Similarly draw a quadrant of a circle with B as the center and A, C as the end points of the arc. Inscribe a circle Γ touching the […]

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December 2, 2012
Regional Mathematics Olympiad (RMO) 2012
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November 15, 2012
Complex Numbers versus Projective Geometry - One problem, Two solutions

The Problem Suppose ABC is any triangle. D, E, F are points on BC, CA, AB respectively such that $latex (\frac{BD}{DC} = \frac{CE}{EA} = \frac{AF}{FB})$. Prove that the centroids of triangles ABC and DEF coincide. A little Complex Number Let A, B, C be points on the Complex plane with complex coordinates a, b, c. […]

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November 13, 2012
Is it a prime number?

353 is a prime number. So is 7919 (in fact it is the 1000th prime). There are 25 primes between 1 and 100. From 1 to 1000 there are 168 of them. It is difficult to check whether a number is prime or not. One simple method is to try and divide the number with […]

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September 7, 2012
An application of Menalaus' theorem

Given: AB is the diameter of a circle with center O. C be any point on the circle. OC. is joined. Let Q be the midpoint of OC. AQ produced meet the circle at E. CD be perpendicular to diameter AB. ED and CB are joined. R.T.P. : CM = MB Construction: AC and BD […]

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