Case 2: p is an odd primeThis now requires the idea of Lifting the Exponents. Please read here if you don't know it.It is an advanced technique to deal with Diophantine Equations.Let's check that the conditions of the LTE are satisfying here.p is an odd prime. gcd(a,b) = 1.p doesn't divide a or b as we are looking for fundamental solutions.\( a^p = a mod p; b^p = b mod p \).Hence, \( a^p + b^p = a + b mod p \).So, p | a+b, and p don't divide a or b. Hence, we can apply LTE.
[/et_pb_tab][et_pb_tab title="Hint 4" _builder_version="4.0" hover_enabled="0"]Using the LTE idea, we get
Then since
, we have that
, so
Now, you see this can't happen for large p, as the LHS is exploding too fast like exponential as p increases and RHS is linear in p.So, we will apply inequality to prove this and find a bound for p for which it works and search in that bound.Note that
or
if
.Therefore, we must have that
(or vice versa). But clearly
, so no solution.QED
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