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October 8, 2017
RMO 2017 Goa and Maharashtra

Let's solve the Regional Mathematics Olympiad Problem, RMO 2017 from Goa and Maharashtra. Try the problems and check your solutions here. (\ 1).((\ 16) marks)Consider a chessboard of size (\ 8) units(\ \times8) units (i.e., each small square on the board has a side length of (\ 1) unit).Let (\ S) be the set of […]

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October 8, 2017
Regional Math Olympiad 2017

Here are the questions asked in Regional Math Olympiad 2017 and their solutions. Try to solve it first and then see the solutions. Looking for just the problems? Download the PDF here. RMO 2017, Problem 1: Let AOB be a given angle less than \( 180^o \) and let P be an interior point of […]

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September 16, 2017
Ceva's Theorem - RMO 2002 Problem 1

Let's discuss a problem based on Ceva's Theorem from Regional Mathematics Olympiad, RMO, 2002, Problem 1. Watch, learn and enjoy.

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August 22, 2017
Pre RMO 2017

How many positive integers less than \(1000\) have the property that the sum of the digits of each such number is divisible by \(7\) and the number itself is divisible by \(3\) ? Suppose \(a,b\) are positive real numbers such that \(a\sqrt{a}+b\sqrt{b}=183\). \(a\sqrt{b}+b\sqrt{a}=182\). Find \(\frac{9}{5}(a+b)\). A contractor has two teams of workers: team A and […]

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January 31, 2017
Congruency is an equivalence relation
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December 14, 2016
Regional Math Olympiad (India) Geometry Problems
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December 14, 2016
Regional Math Olympiad (India) Algebra Problems
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December 14, 2016
Regional Math Olympiad (India) Number Theory Problems

Here is the post for the Regional Mathematics Olympiad (India) RMO Number Theory Problems. These are problems from previous year papers. (This is a work in progress. More problems will be added soon). RMO Number Theory Problems: Find all triples (p, q, r) of primes such that pq = r + 1 and 2(p 2 […]

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October 21, 2016
RMO 16-OCT-2016-1 Solution

wb-rmo-2016-1-google-docs

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October 16, 2016
RMO 2016 Karnataka, Assam, Andhra Pradesh (except Telangana), West Bengal Region

Problems Problem 1 Let \( a, b, c \) be positive real numbers such that $$ \frac{a}{1+a} + \frac{b}{1+b} + \frac{c}{1+c} = 1 $$ Prove that \( abc \leq \frac{1}{8} \)

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