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October 1, 2018
Interior Segment is small - RMO 2009 Geometry

A convex polygon \( \Gamma \) is such that the distance between any two vertices of \( \Gamma \) does not exceed 1. Prove that the distance between any two points on the boundary of \( \Gamma \) does not exceed 1. If X and Y are two distinct points inside \( \Gamma \), prove that […]

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September 29, 2018
ফ্রি গ্রুপের গ্রোমোভ সীমান্তে একলা থাকেন ক্যান্টর

মানচিত্র আঁকছিলাম। রাস্তা গুলো সোজা সোজা। উত্তর, দক্ষিণ, পুব, পশ্চিমে যাওয়া যায়। এক ধাপ ডাইনে গেলে, সঙ্গে সঙ্গে এক ধাপ বাঁয়ে ফেরার নিয়ম নেই। (তাহলে আর ডাইনে গেলাম কেন!) তেমনি একধাপ উত্তরে গেলে, সঙ্গে সঙ্গে একধাপ দক্ষিণে ফেরাও মানা। 

মানচিত্র আঁকতে আঁকতে দেখলাম এক উদ্ভট দেশ তৈরি হচ্ছে। সে দেশের প্রতি চৌমাথায় অসীম সব রাস্তা। সে সব রাস্তা আবার একে অপরের সঙ্গে তেমন দেখা সাক্ষাৎ করে না। এ হেন দেশের সীমান্ত নিয়ে আমাদের যত মাথা ব্যাথা। খুঁজতে খুঁজতে বেড়িয়ে পড়ল এক আজব কিস্যা!

সীমান্তে একলা দাঁড়িয়ে আছেন ক্যান্টর। 

বাকি আড্ডা ভিডিও তে।

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September 24, 2018
Sine Rule and Incenter - RMO 2009 Geometry

The Problem Let ABC be a triangle in which AB = AC and let I be its in-centre. Suppose BC = AB + AI. Find ∠BAC. Big Ideas For any triangle ABC, \( \frac{\sin A}{a} = \frac{\sin B } {b} = \frac {\sin C }{c} \). Addendo: If \( \frac{a}{b} = \frac{c}{d} \) then each of […]

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September 18, 2018
Cheenta and Singapore Method - creating Mathematicians of the future

Recently, French mathematician Cedric Villani's team came up with '21 measures for the teaching of Mathematics'. I read through the report, with great curiosity. I happily noted that Cheenta's Thousand Flowers program has already implemented some of his recommendations.

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September 15, 2018
RMO 2008 Problem 6 Solution - Pythagoras Extended!

Pythagoras theorem can be extended! What happens if the triangle is obtuse-angled (instead of right-angled?) We explore the idea by using a problem from Math Olympiad.

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September 11, 2018
A rejoinder to the 'Discovery'
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September 3, 2018
RMO 2008 Solution of Problem 1 Cyclic Pentagon

Problem Let ABC be an acute-angled triangle, let D, F be the mid-points of BC, AB respectively. Let the perpendicular from F to AC and the perpendicular at B to BC meet in N. Prove that ND is equal to circum-radius of ABC. Theorems and tools The discussion uses the following Theorems: Midpoint Theorem: The line […]

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September 2, 2018
TIFR 2017 Math Solution -Set of Nilpotent Matrices

TIFR 2017 Math Solution is a part of TIFR entrance preparation series. The Tata Institute of Fundamental Research is India's premier institution for advanced research in Mathematics. The Institute runs a graduate programme leading to the award of Ph.D., Integrated M.Sc.-Ph.D. as well as M.Sc. degree in certain subjects. The image is a front cover […]

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September 1, 2018
I.S.I. Entrance Solution Sequence of isosceles triangles -2018 Problem 6
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August 29, 2018
I.S.I. Entrance 2018 Problem 7 | Bases, Exponents and Role reversals

This is a problem from ISI B.Stat-B.Math Entrance Exam 2018, Subjective Problem 7. It is based on Bases, Exponents and Role reversals. I.S.I. Entrance 2018 Problem 7 Let $(a, b, c)$ are natural numbers such that $(a^{2}+b^{2}=c^{2})$ and $(c-b=1)$. Prove that(i) a is odd.(ii) b is divisible by 4(iii) $( a^{b}+b^{a} )$ is divisible by […]

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