Let's discuss a beautiful problem useful for Physics Olympiad based on Motion under Constant Gravity.
The Problem: Motion under Constant Gravity
A person throws vertically up n balls per second with the same velocity. He throws a ball whenever the previous one is at its highest point. The height to which the balls rise is
(a) g/n2
(b) 2gn
(c) g/2n2
(d) 2gn2
Solution:
We know v=u-gt. v is zero at the highest point. Time t taken by one ball to reach maximum height is 1/n.
Hence, we have
u=gt
or, u=g/n……. (i)
now, from the relation v2=u2-2gh. Again, v=0
u2=2gh……. (ii)
Putting the value of u from equation (i) in above relation (ii), we get
h=g/2n2.
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