Let's discuss a beautiful problem useful for Physics Olympiad based on Motion under Constant Gravity.
The Problem: Motion under Constant Gravity
A person throws vertically up n balls per second with the same velocity. He throws a ball whenever the previous one is at its highest point. The height to which the balls rise is
(a) g/n2
(b) 2gn
(c) g/2n2
(d) 2gn2
Solution:
We know v=u-gt. v is zero at the highest point. Time t taken by one ball to reach maximum height is 1/n.
Hence, we have
u=gt
or, u=g/n……. (i)
now, from the relation v2=u2-2gh. Again, v=0
u2=2gh……. (ii)
Putting the value of u from equation (i) in above relation (ii), we get
h=g/2n2.
In 2026, the following Cheenta students have been successful for Indian Statistical Institute's M.Stat Entrance. They ranked within the first 50 in the entire country in these entrances. I.S.I. M.Stat Entrance
In 2026, the following Cheenta students have been successful for Indian Statistical Institute's B.Stat Entrance and Chennai Mathematical Institute's B.Sc. Math Entrance. They ranked within the first 200 in the entire country in these entrances. Most of these students attended the problem solving workshops regularly, which happen 5 days every week. CMI B.Sc. Math Entrance […]
In 2025, 8 students from Cheenta Academy cracked the prestigious Regional Math Olympiad. In this post, we will share some of their success stories and learning strategies. The Regional Mathematics Olympiad (RMO) and the Indian National Mathematics Olympiad (INMO) are two most important mathematics contests in India.These two contests are for the students who are […]
Cheenta Academy proudly celebrates the success of 27 current and former students who qualified for the Indian Olympiad Qualifier in Mathematics (IOQM) 2025, advancing to the next stage — RMO. This accomplishment highlights their perseverance and Cheenta’s ongoing mission to nurture mathematical excellence and research-oriented learning.