RMO 2018 Tamil Nadu Problem 2 is from Theory of Equations. We present sequential hints for this problem. Do not read all hints at one go. Try it yourself.
Find the set of all real values of a for which the real polynomial equation $ P(x) = x^2 - 2ax + b = 0 $ has real roots, given that $ P(0) \cdot P(1) \cdot P(2) \neq 0$ and $( P(0), P(1), P(2) )$ form a geometric progression.
Also see
P(0) = b (plug in x = 0 in the given quadratic). P(1) = 1 - 2a + b and P(2) = 4 - 4a + b.
Since P(0), P(1) and P(2) are in Geometric Progression, hence $P(0) \times P(2) = P(1)^2$. This balls down to $$ b \cdot (4 - 4a + b) = (1 - 2a + b)^2 $$. Simplify this expression.
$ b \cdot (4 - 4a + b) = (1 - 2a + b)^2 \ \Rightarrow 4b - 4ab + b^2 = 1 + 4a^2 + b^2 - 4a - 4ab + 2b \ \Rightarrow 2b = 4a^2 - 4a + 1 $
Discriminant of a quadratic equation $ ax^2 + bx + c = 0$ is $ b^2 - 4ac $. The quadratic equation has real roots iff $ b^2 - 4ac \geq 0 $.
The discriminant of the given quadratic is $$ 4a^2 - 4b $$ From Hint 2, we know $$ 4b = 8a^2 - 8a + 2 $$ Hence the discriminant is $$ 4a^2 - (8a^2 - 8a + 2) = -4a^2 + 8a - 2 $$
We want this discriminant to be non negative.
$$ -4a^2 + 8a - 2 \geq 0 \Rightarrow 2a^2 - 4a + 1 \leq 0 $$
Use the quadratic formula to find the roots of the quadratic $ 2a^2 - 4a + 1 $(this will allow us to factorize the expression).
The roots are $$ \frac { 4 \pm \sqrt {16 - 8}}{2} = 2 \pm \sqrt {2} $$
Hence $a \in [2 - \sqrt 2, 2 + \sqrt 2] $
Also see

Publishing original scientific research in a peer-reviewed journal is an achievement many scholars work toward for years. Achieving this feat early in one's academic journey requires exceptional intellectual rigor, creativity, and persistence. Aaditya Punatar and Muskan Sadana have reached this remarkable milestone, successfully publishing their collaborative research paper in the prestigious Journal of Emerging Investigators […]

Her project on quantum-accelerated Steiner trees for 15-minute cities earned a place among the finalists at the world's largest pre-college STEM competition. Prishaa Shrimali of Marymount School of New York, was selected as a Grand Finalist at the 2026 Regeneron International Science and Engineering Fair (ISEF) in Phoenix, Arizona. Her project was Optimizing Urban Accessibility: […]

In 2026, the following Cheenta students have been successful for Indian Statistical Institute's M.Stat Entrance. They ranked within the first 50 in the entire country in these entrances. I.S.I. M.Stat Entrance

In 2026, the following Cheenta students have been successful for Indian Statistical Institute's B.Stat Entrance and Chennai Mathematical Institute's B.Sc. Math Entrance. They ranked within the first 200 in the entire country in these entrances. Most of these students attended the problem solving workshops regularly, which happen 5 days every week. CMI B.Sc. Math Entrance […]