A beautiful problem form American Math Contest (AMC 10A) 2006, Problem 21 solution. Key idea is to use basic calculation.
A beautiful problem form American Math Contest (AMC 10A) 2006, Problem 21 solution. Key idea is to use basic calculation.
AMC 10A 2013, Problem 21 needed a clever trick to play with numbers. See the solution with sequential hints.
AMC 10A 2014, Problem 24 needed a clever trick of number theory. See the solution with sequential hints. A sequence of natural numbers is constructed by listing the first
This problem is a very basic, tricky and intuitive application resulting in the solutions of a diophantine equation and unique representation of a number. Try with our sequential hints.
This problem is an intermediate application of the polynomials and invoking a cute number theoritic argument to make it a good problem to try with our sequential hints.
So we all know about Hardy-Ramanujan Number 1729. I found some extensions of these type of number we are really mind cracking and amazing.
American Math Contest (AMC 10A) 2007, Problem 20 solution. Well, this is a very basic but interesting algebra problem where we can play with squares.
This problem is an intermediate application of basic number theoritical principles. from Italy MO Solve this problem with the help of Sequential Hints.
AMC 10A 2015, Problem 22 needed a clever trick of probability and combinations and playing with numbers. See the solution with sequential hints.
AMC 10A 2016 Problem 22 solution. See the solution with sequential hints. For some positive integer, the number has positive integer divisors