Try this beautiful Problem from Algebra based on Pen & Note Books from PRMO 2019.
A pen costs Rs.$13$ and a notebook costs Rs.$17$. A school spends exactly Rs.$10000$ in the year $2017 - 18$ to buy $x$ pens and $y$ notebooks such that $x$ and $y$ are as close as possible (i.e. $|x-y|$ is minimum). Next year, in $2018-19,$ the school spends a little more than Rs.$10000$ and buys $y$ pens and $x$ notebooks. How much more did the school pay?
Algebra
Equation
multiplication
Answer:$40$
PRMO-2019, Problem 16
Pre College Mathematics
Given A pen costs Rs.\(13\) and a note book costs Rs.\(17\)
Nunber of pens \(x\) and numbers of notebooks \(y\)
According to question
\(13 x+17 y=10,000\) ..........................(1)
\(17 x+13 y=10000+P\)......................(2)
Where $\mathrm{P}$ is little more amount spend by school in $2018-19$.we have to find out the value of \(P\).Can you find out?
Can you now finish the problem ..........
Adding (1) & (2)
$x+y=\frac{20,000+P}{30}$
Subtract (1) form (2)
$x-y=\frac{P}{4}$
Let $P=4 a$
$\begin{aligned} \text { So, } x+y=& \frac{20,000+4 a}{30} \ &=666+\frac{10+2 a}{15} \end{aligned}$
Therefore \(a\)=\(10\)
Can you finish the problem........
Since $P=4 a$ \(\Rightarrow P=40\)
So school had to pay Rs. $40$ extra in $2018 - 2019$
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