Points \(A, B, C, D, E\) lie on a circle \(\omega\) and point \(P\) lies outside the the circle. The given points are such that
(I) Lines \(PB\) and \(PD\) are tangents to \(\omega\);
(II) \(P, A, C\) are collinear;
(III) Line \(DE\) is parallel to line \(AC\).
Prove that line \(BE\) bisects line \(AC\)