[swastik pramanik]

A triangle ABC is inscribed in a circle of radius 1, with <BAC = 60 degree. Altitudes AD and BE of triangle ABC intersect at H. Find the smallest possible value of the length of the segment AH.

[Tarit Goswami]

First observe that length of the segment \( AH = 2R\cos{\angle{BAC}} \) , where \( R\) is the circumradius.

So, $$AH = 2\cdot \cos{60^o} = 1$$

[Author]

Posts