[Manya Lohumi]

problem - 5

Answer - max possible multiple of 6 by the product of  2 dices = 6×6=36

6×1=6   ,    6+1=7

6×2=12  ,   6+2=8

6×3=18  ,   6+3=9

6×4=24  ,   6+4=10

6×5=30  ,   6+5=11

6×6=36  ,   6+6=12

2×3=6    ,    2+3=5 — these are all the possible products of 6 by rolling 2 dices and their sum.

Hence we found that 6 can't be the sum of the 2 numbers rolled because it is not in the table made by us.

Option- ( B )- 6

• This reply was modified 1 year, 7 months ago by Manya Lohumi.

[Manya Lohumi]

Problem -6

Answer - I think that to do this problem we just need to visualise and guess the answer which is really simple .
The answer is Option - (B) - P,R,Q,S.

• This reply was modified 1 year, 7 months ago by Manya Lohumi.

[Manya Lohumi]

Problem - 8

Answer

MONDAY

$2

TUESDAY

$ 4/5

WEDNESDAY

$8/10/7/8

THURSDAY

$11/16/20/23/14/10

 

note - all the calculation is without repetition   

Option - ( D ) - 6

 

 

• This reply was modified 1 year, 7 months ago by Manya Lohumi.
• This reply was modified 1 year, 7 months ago by Manya Lohumi.
• This reply was modified 1 year, 7 months ago by Manya Lohumi.

[Manya Lohumi]

Problem - 12

Answer - there are 90 guppies in total

let the number of guppies in the first tank be - A

As there is 1 more guppi in the 2nd tank than 1st tank  so there are

A+ 1 guppies in the second tank.

As there are 2 more guppies in the 3rd tank than the second tank so there are

A+ 3 guppies in the third tank.

As there are 3 more guppies in the 4th tank than the third tank so there are

A+6 guppies in the 4th tank.

If the sum this information we get that

A+(A+1)+(A+3)+(A+6)= 4 A+10 = 90

So we get that A=20

And as the fourth tank = A+6 = 20+6= 26

So the number of guppies in the 4th tank = 26

Option- (E) - 26

• This reply was modified 1 year, 7 months ago by Manya Lohumi.

[Manya Lohumi]

Problem - 14

Answer - the samllest path from A to Z is -

AX+XM+MY+YC+CZ = 5+2+6+5+10 = 28

The answer is -

Option - (A) - 28

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