Try this beautiful problem from Singapore Mathematics Olympiad, SMO, 2011 based on Permutation.
A \(4 \times 4\) Sudoku grid is filled with digits so that each column , each row and each of the four \( 2 \times 2\) sub grids that composes the grid contains all of the digits from 1 to 4. For example
Permutations & Combinations
Sudoku
Set Theory
Answer: 288
Singapore Mathematical Olympiad
Challenges and Thrills - Pre - College Mathematics
If you really get stuck in this problem here is the first hint to do that:
At 1st let's consider the sub grids of \( 2 \times 2\) filled with 1-4 ( 1, 2 , 3 ,4)
If a,b,c,d are all distinct , and there are no other numbers to place in x . If {a,b} = {c,d} then again a',b',c,d are all distinct , and no other number can be possible for x'.
We need to understand that the choices we have ,
{a,a'} = {1,2} , {b,b'} = {3,4}, {c,c'} = {2,4} and {d,d'} = {1,3}
Among these choices \( 2^4 = 16 \) choices 4 of them are impossible - {a,b} = {c,d} = {1,4} or {2,3} and
{a,b} = {1,4} and {c,d} = {2,3} and {a,b} = {2,3} and {c,d} = {1,4}
Try rest....
Now for each remaining case a',b',c' and d' are uniquely determined so
{x} = {1,2,3,4} - {a,b} \(\cup\) {c,d}
{y} = {1,2,3,4} - {a,b} \(\cup\) {c',d'}
{x'} = {1,2,3,4} - {a',b'} \(\cup\) {c,d}
{y'} = {1,2,3,4} - {a',b'} \(\cup\) {c',d'}
In final hint :
There are 4! = 24 permutation in the left top grid we can find. So total 12 * 24 = 288 possible 4\(\times\) 4 Sudoku grids can be found.
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